answer:The gain on disposal of a trading investment is considered an equity account and is typically reported in the "Other Revenues and Expenses" section of the income statement. This reflects the increase in the owner's equity due to the transaction.

answer:The heat released in the given reaction is related to the number of moles of rust (Fe2O3) formed. According to the balanced equation, 1.65 × 10^3 kJ of heat is released for the formation of 2 moles of Fe2O3. To find out how much rust is formed when 200.0 kJ of heat is released, we can set up a proportion: {eq}frac{1.65 times 10^3 text{ kJ}}{2 text{ mol Fe}_2text{O}_3} = frac{200.0 text{ kJ}}{X text{ mol Fe}_2text{O}_3} {/eq} Solving for X: {eq}X = frac{200.0 text{ kJ} times 2 text{ mol Fe}_2text{O}_3}{1.65 times 10^3 text{ kJ}} {/eq} {eq}X = 0.242 text{ mol Fe}_2text{O}_3 {/eq} Now, to find the mass of rust formed, we multiply the number of moles by the molar mass of Fe2O3, which is 159.69 g/mol: {eq}M = 0.242 text{ mol Fe}_2text{O}_3 times 159.69 text{ g/mol} {/eq} {eq}M = 38.6 text{ g} {/eq} Therefore, 38.6 grams of rust (Fe2O3) are formed when 200.0 kJ of heat is released.

answer:Yes, we can find such a subset A. Let m be any measure on R^2 such that m(L) = 0 for every vertical line L ⊆ R^2 (such as any measure that is absolutely continuous with respect to Lebesgue's measure). Then, for every measurable set E ⊆ R^2 with m(E) < ∞, there exists a measurable subset A ⊆ E such that m(A) = m(E)/2. To prove this, we can use the following steps: 1. For each interval I ⊆ R, consider the vertical strip V_I = I × R and let E_I = V_I ∩ E. 2. Fix any real number t_0 and observe that ⋂_{t>t_0} (-infty, t] = (-infty, t_0] and ⋃_{t<t_0} (-infty, t] = (-infty, t_0). 3. Consequently, ⋂_{t>t_0} E_{(-infty, t]} = E_{(-infty, t_0]} and ⋃_{t<t_0} E_{(-infty, t]} = E_{(-infty, t_0)}. 4. Using that E has finite measure, we deduce that inf_{t>t_0} m (E_{(-infty, t]}) = m (E_{(-infty, t_0]}) and sup_{t<t_0} m (E_{(-infty, t]}) = m (E_{(-infty, t_0)}). 5. Because positive measures are monotonic functions, we also get lim_{t→t_0^+} m (E_{(-infty, t]}) = m (E_{(-infty, t_0]}) and lim_{t→t_0^-} m (E_{(-infty, t]}) = m (E_{(-infty, t_0)}). 6. Regarding the function f(t) := m (E_{(-infty, t]}), we conclude from the first identity above that f is right-continuous. 7. Moreover, referring to the degenerate interval [t_0, t_0], observe that m (E_{(-infty, t_0]}) = m (E_{(-infty, t_0)}) + m (E_{[t_0 t_0]}) = m (E_{(-infty, t_0)}), where we have used the hypothesis to conclude that m (E_{[t_0 t_0]}) = 0. 8. We therefore also have that f is left-continuous, hence continuous. 9. Since lim_{t→−∞}f(t) = 0 and lim_{t→∞}f(t) = m (E), we can now employ the intermediate value theorem to obtain some t_1 such that f(t_1) = m (E)/2. 10. The desired set A mentioned in the statement can then be taken to be A = E_{(-infty,t_1]}.

answer:John James Audubon, a renowned ornithologist, hunter, painter, and naturalist, is best known for his masterpiece, "The Birds of America." This extraordinary work showcases his exceptional talent in capturing the beauty and diversity of North American birds through stunning illustrations and detailed descriptions. Audubon's dedication to his craft and his innovative approach to depicting birds in their natural habitats revolutionized the field of ornithology and left a lasting legacy in the world of art and science. The Birds of America