Appearance
question:How do I find the value of the cosecant function for the angle ( frac{11pi}{6} )?
answer:To find the value of ( cscleft(frac{11pi}{6}right) ), we first need to determine the sine of the angle ( frac{11pi}{6} ). Using the fact that the sine function has a period of ( 2pi ), we can rewrite the angle as ( frac{11pi}{6} = -frac{pi}{6} + 2pi ). Since sine is an odd function, ( sin(-theta) = -sin(theta) ). Therefore, [ sinleft(-frac{pi}{6}right) = -sinleft(frac{pi}{6}right) = -frac{1}{2} ] Now, the cosecant function is the reciprocal of the sine function, which means: [ cscleft(frac{11pi}{6}right) = frac{1}{sinleft(frac{11pi}{6}right)} = frac{1}{-frac{1}{2}} = -2 ] Thus, the value of ( cscleft(frac{11pi}{6}right) ) is ( -2 ).
question:Find the least squares vector that minimizes the error when regressing the given data points. The data is represented by the matrix A and the vector b: A = left( begin{array}{ccc} -1 & 2 & -3 -3 & -1 & -3 -3 & 1 & -2 -1 & 3 & -3 0 & -1 & 1 -1 & -1 & 1 end{array} right), quad b = left( begin{array}{c} -2.79 0.66 -2.82 2.32 0.06 1.95 end{array} right) Determine the vector x that satisfies the least squares solution: x = (A^T A)^{-1} A^T b
answer:The least squares vector x for the given matrix A and vector b is: x = left( begin{array}{c} 0.21 -0.203 -0.011 end{array} right)
question:Solve for x in the equation 29 = -27 + x.
answer:To solve for x, follow these steps: 1. Add 27 to both sides of the equation to isolate x on one side: begin{align*} 29 &= -27 + x +27 &quad +27 end{align*} 2. Simplify the equation: begin{align*} 29 + 27 &= x 56 &= x end{align*} Thus, x = 56.
question:What is the range of the set {frac{5}{2}, frac{34}{7}, frac{261}{32}, -frac{19}{7}, frac{20}{3}, 10, 3, frac{3}{2}, -5, frac{291}{32}, frac{34}{7}, 8, 7, 5}?
answer:The range of a set is determined by subtracting its smallest value from its largest value. In the given set: - The largest number is 10. - The smallest number is -5. So, the range is calculated as 10 - (-5) = 10 + 5 = 15. Therefore, the range of the set is 15.