answer:All three courses of action are appropriate. The government should consider relaxing the eligibility criteria to ensure that more businesses can access the financial assistance they need. Businesses that do not qualify should explore other options for funding, and the government should consider providing additional support to those businesses that are struggling but do not meet the current criteria.

answer:When the required reserve ratio is 20%, the bank must hold onto 20% of the deposit as reserves, while the remaining 80% can be loaned out. Reserves Required = 20% of 100 = 20 Available for Lending = 100 - 20 = 80 Therefore, the bank can make additional loans of 80.

answer:The sequence (a_n) has the property that a_{mn} = a_m a_n for coprime integers m and n. Let's establish the base cases: 1. a_1 = 1 (from the strictly increasing nature of the sequence and the fact that a_2 = 2). 2. a_3 = 3 (using a_{15} < a_{18} < 2a_{10} and the monotonicity of the sequence). 3. a_4 = 4 and a_5 = 5 (by considering a_6 = a_2a_3 and the order of the sequence). Now, suppose we have proven a_j = j for all j < k, where k > 6. We will show that a_k = k. To find such an a_k, consider the smallest even number l geq k that is not a power of 2. We have l-k leq 3 (since two consecutive numbers among k, k+1, k+2, k+3 are even, and one of them is not a power of 2). Note that l can be written as l = 2^r m, where m is odd, and r > 0. Since k > l-4, we have 2^r < k and m < k. Using the sequence's properties, we get a_l = a_{2^r}a_m = 2^rm = l. Now, to show a_k = k, we use the fact that a_{k-1} < a_k < a_{k+1} < dots < a_{l-1} < a_l = l. Since a_j = j for all j < l, the only way to maintain the strict increase is if a_k = k. By induction, the claim is proven for all positive integers n, as any n can be expressed as a product of coprime factors, and we can apply the property of the sequence to deduce a_n = n. Furthermore, this result is related to the more general theorem that any strictly increasing multiplicative non-constant function f: mathbb{N} to mathbb{R} must be of the form n^{alpha} for some alpha > 0. In our case, alpha = 1.

answer:1. Pap smear - A 2. Amniocentesis - B 3. Mammography - C 4. Colposcopy - D