answer:Net Working Capital for 2013 = Current Assets (2013) - Current Liabilities (2013) = (1,700 + 1,200 + 3,800 + 1,900 + 750) - (5,300 + 300 + 1,500) = 9,350 - 7,100 = 2,250 Net Working Capital for 2012 = Current Assets (2012) - Current Liabilities (2012) = (1,561 + 1,052 + 3,616 + 1,816 + 707) - (5,173 + 288 + 1,401) = 8,752 - 6,862 = 1,890 Change in Net Working Capital = Net Working Capital (2013) - Net Working Capital (2012) = 2,250 - 1,890 = 360

answer:Yes, you can utilize the trigonometric identity cos^2theta + sin^2theta = 1 to eliminate theta. Starting with the given parametric equations, express costheta and sintheta in terms of x and y: 2x = costheta y = sintheta Now, square both equations and add them together to apply the identity: (2x)^2 + y^2 = cos^2theta + sin^2theta 4x^2 + y^2 = 1 Since theta is restricted to the domain 0 leq theta leq pi, it implies that sintheta geq 0, which in turn means y geq 0. Thus, the Cartesian equation representing the curve is: begin{eqnarray*} 4x^2 + y^2 = 1 quad text{for} quad y geq 0 end{eqnarray*}

answer:The notation dmathbb{Z}/nmathbb{Z} represents the quotient set of the set of all integer multiples of d by the set of all integer multiples of n, where d divides n. To understand this, consider the sets dmathbb{Z} = {d cdot k : k in mathbb{Z}} and nmathbb{Z} = {n cdot k : k in mathbb{Z}}. For the specific case of 2mathbb{Z}/12mathbb{Z}, we have the set of all even integers (i.e., 2mathbb{Z}) being divided by the set of all multiples of 12 (i.e., 12mathbb{Z}). The elements of 2mathbb{Z}/12mathbb{Z} are equivalence classes formed by the cosets of 12mathbb{Z} within 2mathbb{Z}. Each element in this quotient set can be represented by a unique residue modulo 12 that is also an even number. Thus, 2mathbb{Z}/12mathbb{Z} = {overline{0}, overline{2}, overline{4}, overline{6}, overline{8}, overline{10}}. Here, the bar notation overline{x} denotes the equivalence class of all integers that differ from x by a multiple of 12. The general approach to understanding dmathbb{Z}/nmathbb{Z} is to represent dmathbb{Z} and nmathbb{Z} as sets, then consider the set of cosets {x+nmathbb{Z} : x in dmathbb{Z}}. Each coset in this set represents an element of the quotient, and elements within the same coset are equivalent modulo n.

answer:From the balanced chemical equation: {eq}Cu(s)+2AgNO3(aq)rightarrow Cu(NO_{3})_{2}(aq)+2Ag(s) {/eq} We can see that the mole ratio of Cu(s) to Ag(s) is 1:2. Therefore, moles of Ag(s) produced = 2 x moles of Cu(s) = 2 x 5.00 mol = 10.00 mol Molar mass of Ag(s) = 107.87 g/mol Therefore, mass of Ag(s) produced = moles of Ag(s) x molar mass of Ag(s) = 10.00 mol x 107.87 g/mol = 1078.7 g