answer:The mole fraction of oxygen in air is 0.2095. According to Dalton's law of partial pressures, the partial pressure of oxygen is equal to the mole fraction of oxygen multiplied by the total pressure. Therefore, the partial pressure of oxygen in air at sea level is: 0.2095 x 1 atm = 0.2095 atm

answer:Carnivores contribute to global warming primarily through the consumption of meat. The demand for meat leads to increased livestock production, particularly beef cattle. Cattle produce significant amounts of methane and carbon dioxide as they metabolize their food. Methane is a potent greenhouse gas, with a global warming potential 25 times greater than carbon dioxide. Additionally, the clearing of forests for grazing land and the production of animal feed contribute to deforestation and the release of carbon dioxide into the atmosphere.

answer:A strong organizational culture is defined by a high consensus and high intensity around core values and beliefs. This means that the majority of employees not only understand but also strongly endorse these key cultural norms. In contrast, a low consensus, high intensity culture would consist of warring factions with differing values, while a low consensus, low intensity culture represents a weak or unclear set of values. The level of consensus and intensity in an organization's culture plays a significant role in determining its overall performance and the attitudes of its members towards the cultural norms.

answer:We have the function {eq}f(x,y) = 4x^2 - 8xy + 3y^3 {/eq} First partial derivatives: {eq}f_x=8,x-8,y {/eq} {eq}f_y= 9,{y}^{2}-8,x {/eq} Second partial derivatives: {eq}f_{xx}=8 f_{yy}= 18y f_{yx}=-8 {/eq} Now, {eq}f_x=0,, Rightarrow , 8,x-8,y =0 f_y=0,, Rightarrow , 9,{y}^{2}-8,x =0 {/eq} The possible critical points are: {eq}left( 0,0 right) left( 1,1 right) {/eq} Second derivative test for: Point: {eq}left( 0,0 right) {/eq} {eq}f_{xx} left( 0,0 right) =8 f_{yy} left( 0,0 right) = 0 f_{xy} left(0,0 right) = -8 {/eq} Hessian is given by: {eq}displaystyle D(a,b)= f_{xx}(a,b).f_{yy}(a,b)-[ f_{xy} (a,b) ]^{2} {/eq} So, Hessian for {eq}left( 0,0 right) {/eq} is: {eq}displaystyle Dleft( 0,0 right) = f_{xx}left(0,0 right) .f_{yy}left( 0,0 right) -[ f_{xy} left( 0,0 right) ]^{2} displaystyle Dleft(0,0 right) =8 cdot 0-[ -8]^2 displaystyle Dleft( 0,0 right) =-64 {/eq} {eq}begin{array} ; ; text{(a,b)} ; & { f_{xx} (a,b) } & { f_{yy} (a,b) } & f_{xy} (a,b) & D(a,b) & Conclusion & (a,b, f(a,b)) hline left( 0,0 right) & 8 & 0 & -8 & -64 & Saddle , point ; & left( 0,0, 0 right) left( 1,1 right) & 8 & 18 & -8 & 80 & Relative , minimum ; & left( 1,1, -1 right) end{array} {/eq}