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question:What type of cell does the cheek cell represent, plant cell or animal cell? How can you tell?

answer:The human cheek cell is an example of a typical animal cell. It has a prominent nucleus and a flexible cell membrane, which gives the cell its irregular, soft-looking shape. Plant cells, on the other hand, have a rigid cell wall and a large central vacuole, which are not present in cheek cells.

question:What is the distinction between P(A|B) and P(B|A), and do they necessarily have the same value?

answer:P(A|B) represents the conditional probability that event A occurs, given that event B has already occurred. On the other hand, P(B|A) denotes the conditional probability that event B takes place, assuming event A has occurred. Mathematically, these probabilities are defined as: [ P(B|A) = frac{P(B cap A)}{P(A)} ] [ P(A|B) = frac{P(A cap B)}{P(B)} ] It's important to note that P(A|B) and P(B|A) are not necessarily equal, as they have different denominators: P(A) in the first case and P(B) in the second. This difference reflects the varying probabilities when considering the occurrence of one event based on the occurrence of the other.

question:Calculate the result of adding 10 to the product of -5 and the difference between -12 and x.

answer:Let's solve this step by step: Difference between -12 and x: -12 - x Product of -5 and the difference: -5(-12 - x) = color{orange}{5(12 + x)} Adding 10 to the product: color{orange}{5(12 + x)} + 10 Therefore, the result is 5(12 + x) + 10.

question:Let f be a non-negative measurable function. Prove that lim_{n to infty} int min(f,n) rightarrow int f without using convergence theorems.

answer:Case 1: int f < infty Fix epsilon > 0. By the definition of the integral, there exists a simple function g le f such that int g > int f - epsilon. Since g is a simple function, it is bounded, so there exists n such that g le n. Therefore, for all n ge n, we have: int min(f,n) ge int g > int f - epsilon. Case 2: int f = infty For any M > 0, there exists a simple function g with g le f and int g ge M. Again, there exists n such that g le n. Thus, for all n ge n, we have: int min(f,n) ge int g ge M. Conclusion In both cases, we have shown that for any epsilon > 0 (or M > 0), there exists n such that for all n ge n, we have |int min(f,n) - int f| < epsilon (or int min(f,n) > M). This implies that: lim_{n to infty} int min(f,n) = int f.

Released under the MIT License.

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