answer:According to the balanced chemical equation, 4 moles of water vapor are required to react with 3 moles of iron to produce 1 mole of {eq}Fe_{3}O_{4}(s) {/eq}. Therefore, if a drying agent is added to the reaction vessel, it will absorb water vapor, thereby decreasing the concentration of water vapor in the reaction mixture. This shift in equilibrium will cause the reaction to proceed in the forward direction, consuming more iron and water vapor to produce more {eq}Fe_{3}O_{4}(s) {/eq}. However, since the drying agent is continuously removing water vapor from the reaction mixture, the equilibrium will not be able to fully shift to the right. As a result, the mass of {eq}Fe_{3}O_{4}(s) {/eq} produced will be less than it would have been if no drying agent were present. If a drying agent is added to absorb water vapor, the mass of {eq}Fe_{3}O_{4}(s) {/eq} will decrease.

answer:The curl of the given vector field vec{F} is calculated as follows: nabla times vec{F} = left| begin{array}{ccc} uvec{i} & uvec{j} & uvec{k} frac{partial}{partial x} & frac{partial}{partial y} & frac{partial}{partial z} f(x, y, z) & g(x, y, z) & h(x, y, z) end{array} right| Substituting the given functions: nabla times vec{F} = left| begin{array}{ccc} uvec{i} & uvec{j} & uvec{k} frac{partial}{partial x} & frac{partial}{partial y} & frac{partial}{partial z} tan (x - y) & sqrt{y} & sqrt{x z} end{array} right| Computing the curl: nabla times vec{F} = left( frac{partial (sqrt{x z})}{partial y} - frac{partial (sqrt{y})}{partial z} right)uvec{i} - left( frac{partial (tan (x - y))}{partial z} - frac{partial (sqrt{x z})}{partial x} right)uvec{j} + left( frac{partial (tan (x - y))}{partial x} right)uvec{k} nabla times vec{F} = left( 0 - 0 right)uvec{i} - left( 0 - frac{z}{2 sqrt{x z}} right)uvec{j} + left( sec^2(x - y) right)uvec{k} Thus, the curl of the vector field is: nabla times vec{F} = left{ 0, frac{z}{2 sqrt{x z}}, sec^2(x - y) right}

answer:To find the total number of cars currently parked in the lot, we need to add the number of cars that were initially parked to the number of cars that arrived later. So, the total number of cars = Initial number of cars + Number of cars that arrived = 17 + 31 = 48 Therefore, there are now 48 cars parked in the hardware store parking lot.

answer:To find the total cost when Q is 20 units, we substitute Q with 20 into the cost equation: {eq}begin{align*} TC &= 160Q - 10Q^2 + 1.2Q^3 &= 160(20) - 10(20)^2 + 1.2(20)^3 &= 3,200 - 4,000 + 9,600 &= 8,800 end{align*} {/eq} Therefore, the total cost to produce 20 units is 8,800.