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question:A person swims across a river at a speed of 2 meters per second relative to the water. The river is flowing east at a speed of 4 meters per second. Find the speed and direction of the person relative to the riverbank.
answer:We assign east to the positive x direction and north to the positive y direction so that the person's velocity vector relative to the water is {eq}vec v_p = left< 0,2 right> {/eq} and the river's velocity vector is {eq}vec v_r = left< 4,0 right> {/eq}. Since the person is in the river, with respect to the riverbank he/she is actually moving with a velocity that is the sum of these two velocities. {eq}begin{align*} vec v &= vec v_p+vec v_r &= left< 0,2 right> + left< 4,0 right> &= left< 4,2 right> end{align*} {/eq} Then the angle as measured counterclockwise from the x-axis is {eq}begin{align*} tan theta &= frac{2}4 theta &approx boldsymbol{ 26.6^circ } end{align*} {/eq} Note that this direction is North of East. The speed of the person with respect to the riverbank is the magnitude of our vector: {eq}begin{align*} | left< 4,2 right> | &= sqrt{ left( 4 right)^2 + left( 2 right)^2} &approx boldsymbol{ 4.472 text{m/s} } end{align*} {/eq}
question:A company manufactures apple butter to supply local vendors. The manufacturing company can produce 330 pounds of apple butter per day, while the demand from vendors is 190 pounds per day. Each time the manufacturing company sets up the production process, it incurs a cost of 176. The annual cost of storing a pound of apples in a refrigerated storage area is 6.50. Determine the optimal ordering quantity and the minimum total annual inventory cost.
answer:To determine the optimal ordering quantity and the minimum total annual inventory cost, we can use the Economic Order Quantity (EOQ) formula: EOQ = √(2AS / H) where: A = Annual demand = 190 pounds per day * 365 days per year = 69,350 pounds per year S = Setup cost = 176 per order H = Holding cost = 6.50 per pound per year Plugging in the values, we get: EOQ = √(2 * 69,350 * 176 / 6.50) = 1937.93 pounds Since we cannot order a fraction of a pound, we round up the EOQ to the nearest whole number, which is 1938 pounds. The total number of orders per year can be calculated as: Number of orders = Annual demand / EOQ = 69,350 pounds / 1938 pounds = 35.78 orders Since we cannot place a fraction of an order, we round up the number of orders to the nearest whole number, which is 36 orders. The average inventory level can be calculated as: Average inventory = EOQ / 2 = 1938 pounds / 2 = 969 pounds The minimum total annual inventory cost can be calculated as: Total cost = (Number of orders * Setup cost) + (Average inventory * Holding cost) = (36 orders * 176 per order) + (969 pounds * 6.50 per pound per year) = 6,336 + 6,303.50 = 12,640 Therefore, the optimal ordering quantity is 1938 pounds, and the minimum total annual inventory cost is 12,640.
question:Calculate the percentage of sales contributed by each product (Heritage and Gorham) for Las Cruces SA, given the following information: - Heritage: - Selling price per unit: €9.00 - Variable expenses per unit: €5.40 - Monthly units sold: 250 - Gorham: - Selling price per unit: €10.00 - Variable expenses per unit: €2.00 - Monthly units sold: 200 - Monthly fixed expenses: €1,000 Round intermediate calculations and the final answer to 2 decimal places.
answer:To find the percentage of sales contributed by each product, we first calculate the monthly sales revenue and variable costs for both products. Heritage: - Revenue = Selling price per unit × Units sold = €9.00 × 250 = €2,250 - Variable cost = Variable expenses per unit × Units sold = €5.40 × 250 = €1,350 Gorham: - Revenue = Selling price per unit × Units sold = €10.00 × 200 = €2,000 - Variable cost = Variable expenses per unit × Units sold = €2.00 × 200 = €400 Total monthly sales revenue = Heritage revenue + Gorham revenue = €2,250 + €2,000 = €4,250 Total monthly variable costs = Heritage variable cost + Gorham variable cost = €1,350 + €400 = €1,750 The break-even point in sales units is when total revenue equals total variable costs: Break-even point = Total monthly variable costs / (Selling price per unit - Variable expenses per unit) For Heritage: €1,350 / (€9.00 - €5.40) = 250 units For Gorham: €400 / (€10.00 - €2.00) = 50 units Total break-even units = 250 + 50 = 300 units The weighted average contribution margin is the sum of the contribution margins of each product divided by the total sales revenue: Weighted average contribution margin = (Heritage contribution margin + Gorham contribution margin) / Total sales revenue Heritage contribution margin = (Heritage revenue - Heritage variable cost) / Total sales revenue Gorham contribution margin = (Gorham revenue - Gorham variable cost) / Total sales revenue Heritage contribution margin = (€2,250 - €1,350) / €4,250 = 0.228571429 Gorham contribution margin = (€2,000 - €400) / €4,250 = 0.300943396 Weighted average contribution margin = (0.228571429 + 0.300943396) / 2 = 0.264757413 ≈ 26.48% The percentage of sales for Heritage is: Heritage % of sales = (Heritage units sold / Total break-even units) × Weighted average contribution margin × 100 = (250 / 300) × 26.48% × 100 ≈ 22.07% The percentage of sales for Gorham is: Gorham % of sales = (Gorham units sold / Total break-even units) × Weighted average contribution margin × 100 = (50 / 300) × 26.48% × 100 ≈ 4.41% Thus, the sales percentages are approximately 22.07% for Heritage and 4.41% for Gorham.
question:Solve the following system of equations: 2x - y = 4 y = -2x + 8
answer:To solve the system of equations, we can use the substitution method. Substitute the value of y from the second equation into the first equation: 2x - (-2x + 8) = 4 Simplify the left side of the equation: 2x + 2x - 8 = 4 Combine like terms: 4x - 8 = 4 Add 8 to both sides of the equation: 4x = 12 Divide both sides of the equation by 4: x = 3 Now that we have the value of x, we can substitute it back into either of the original equations to solve for y. Let's use the second equation: y = -2x + 8 y = -2(3) + 8 Simplify the right side of the equation: y = -6 + 8 Combine like terms: y = 2 Therefore, the solution to the system of equations is x = 3 and y = 2. The solution to the system of equations is x = 3 and y = 2.