answer:In MLA style, a Works Cited page lists all the sources used in a research paper or project. Each entry should include the following information, formatted as follows: 1. Author's Last Name, First Name. 2. "Title of the Article or Individual Webpage." Title of the Website, Name of the Publisher, Date of publication, URL. Example: Smith, John. "The Impact of Technology on Society." Science Daily, Tech Publishing, 2020, www.sciencedaily.com/articles/t/impact_of_tech_on_society.html. Remember to include the appropriate punctuation and indentation for each entry. If the source is from a print publication, include the page range instead of the URL.

answer:The roots of the polynomial can be found using the quadratic formula, x = frac{-b pm sqrt{b^2 - 4ac}}{2a}. For the given polynomial -frac{17x^2}{2} - 11x - 15, the coefficients are a = -frac{17}{2}, b = -11, and c = -15. Applying the formula: x = frac{-(-11) pm sqrt{(-11)^2 - 4left(-frac{17}{2}right)(-15)}}{2left(-frac{17}{2}right)} x = frac{11 pm sqrt{121 - 1020}}{-17} x = frac{11 pm sqrt{-909}}{-17} Since the discriminant is negative, the roots are complex: x = frac{11 pm sqrt{909}i}{-17} x = frac{11 pm 3sqrt{101}i}{-17} x = frac{1}{17} left(-11 pm 3sqrt{101}iright) Hence, the roots are x = frac{1}{17} left(-11 - 3sqrt{101}iright) and x = frac{1}{17} left(-11 + 3sqrt{101}iright).

answer:Part A The magnitude of the electric field at the midpoint between the two disks is: {eq}E = frac{1}{4pivarepsilon_0}frac{2q}{d^2} E = frac{1}{4pi(8.85times10^{-12}text{ C}^2/text{Nm}^2)}frac{2(50times10^{-9}text{ C})}{(0.26text{ m})^2} E = 7.2times10^5text{ N/C} {/eq} The direction of the electric field is from the positive disk to the negative disk. Part B The direction of the electric field to the left of the disk is to the right. The direction of the electric field to the right of the disk is to the left. The direction of the electric field parallel to the plane of the disks is zero. Part C The force on a -3.0 nC charge placed at the midpoint is: {eq}F = qE F = (-3.0times10^{-9}text{ C})(7.2times10^5text{ N/C}) F = -2.2times10^{-3}text{ N} {/eq} The negative sign indicates that the force is in the opposite direction to the electric field, which is towards the negative disk. Part D The direction of the force on a -3.0 nC charge placed to the left of the disk is to the right. The direction of the force on a -3.0 nC charge placed to the right of the disk is to the left. The direction of the force on a -3.0 nC charge placed parallel to the plane of the disks is zero.

answer:Using the substitution {eq}u=a^x {/eq}, we have {eq}du=a^x ln a , dx {/eq}. When {eq}x=0 {/eq}, {eq}u=1 {/eq}, and when {eq}xtoinfty {/eq}, {eq}utoinfty {/eq}. Therefore, the integral becomes: {eq}begin{align*} int_0^infty frac{ln(a^x)}{x^2} , dx&=int_1^infty frac{ln u}{(ln a)^2 u^2} , du &=frac{1}{(ln a)^2}int_1^infty frac{ln u}{u^2} , du &=frac{1}{(ln a)^2}cdot1&text{(using the result from the original question/answer pair)} &=frac{1}{(ln a)^2} , . end{align*} {/eq}