answer:Circuit training is the most suitable workout for enhancing muscular endurance. It involves a continuous sequence of exercises that engage and contract specific muscle groups. By consistently performing these exercises, the muscles become stronger and capable of enduring more weight for an extended period. Regular circuit training gradually increases muscle tone, strength, and endurance.

answer:1) Prophase: During this phase, the chromatin condenses into visible chromosomes, the nuclear envelope breaks down, and the mitotic spindle begins to form. 2) Metaphase: In metaphase, the chromosomes align at the equator of the cell, also known as the metaphase plate. The spindle fibers attach to the centromeres of the chromosomes. 3) Anaphase: During anaphase, the sister chromatids are pulled apart by the mitotic spindle fibers, moving toward opposite poles of the cell. 4) Telophase: A new nuclear envelope starts to form around each set of chromosomes, and the chromosomes begin to decondense. Two distinct nuclei are now present within the cell. 5) Cytokinesis: This phase follows telophase, during which the cytoplasm and organelles divide, ultimately resulting in the formation of two daughter cells. These five stages collectively complete the process of cell division, ensuring that each daughter cell receives an identical set of genetic material.

answer:Given: - Population mean, μ = 18.46 gallons - Population standard deviation, σ = 5 gallons - Required percentile, P(X < M) = 0.98 The Z-score corresponding to 0.98 percentile is approximately Z_m = 2.054. Using the Z-score formula: Z = (X - μ) / σ For P(Z < Z_m), we have: X = M (the threshold consumption) Z = 2.054 So, M = μ + Z_m * σ Substituting the values: begin{align*} M &= 18.46 + 2.054 times 5 &= 18.46 + 10.27 &= 28.73 text{ gallons} end{align*} Therefore, 98% of the people in Country A consumed less than 28.73 gallons of soft drinks.

answer:The equation of a plane passing through three points A(x1, y1, z1), B(x2, y2, z2), and C(x3, y3, z3) can be found using the following steps: 1. Calculate the cross product of vectors AB and AC to find the normal vector (n) of the plane. 2. Use the point-normal form of the equation: n·(P - A) = 0, where P(x, y, z) is any point on the plane. First, let's find the vectors AB and AC: AB = <5 - (-4), 2 - 5, -3 - (-1)> = <9, -3, -2> AC = <(-4) - (-4), -1 - 5, 5 - (-1)> = <0, -6, 6> Now, we find the normal vector (n) by taking the cross product of AB and AC: n = AB × AC = <(-3)(6) - (-2)(-6), (-2)(0) - (9)(6), (9)(-6) - (-3)(0)> n = <-18 + 12, 0 - 54, -54> Simplify the normal vector: n = <-6, -54, -54> Now, we will use the point A (-4, 5, -1) and the normal vector n to form the equation of the plane: n·(P - A) = <-6, -54, -54>·(<x - (-4), y - 5, z - (-1)>) = 0 -6(x + 4) - 54(y - 5) - 54(z + 1) = 0 Simplify the equation: -6x - 24 - 54y + 270 - 54z - 54 = 0 -6x - 54y - 54z + 270 - 24 - 54 = 0 -6x - 54y - 54z + 192 = 0 Divide by the coefficient of x to simplify: x + 9y + 9z - 32 = 0 Hence, the equation of the plane is: x + 9y + 9z - 32 = 0