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question:Analyze Ivanhoe Company's liquidity and solvency based on the following ratios computed from the given balance sheet data: * Current ratio * Accounts receivable turnover * Average collection period * Inventory turnover * Days in inventory

answer:Liquidity: * Current ratio (2.90:1): Indicates that Ivanhoe Company has 2.90 of current assets for every 1 of current liabilities, suggesting strong liquidity. * Accounts receivable turnover (5.20 times): Shows that the company collects its accounts receivable 5.20 times per year, indicating efficient collection practices. * Average collection period (69 days): It takes the company an average of 69 days to collect its accounts receivable, which is within a reasonable range. Solvency: * Inventory turnover (3.66 times): The company sells and replaces its inventory 3.66 times per year, indicating moderate inventory management efficiency. * Days in inventory (98 days): Inventory remains in stock for an average of 98 days, which could suggest room for improvement in inventory management. Overall, Ivanhoe Company appears to have strong liquidity, with a high current ratio and efficient accounts receivable collection practices. However, its inventory turnover and days in inventory suggest opportunities for improvement in inventory management, which could potentially enhance its solvency.

question:How do you find the composite functions #f(g(x))# and #g(f(x))# when #f(x)=4x^2# and #g(x)=-x+3#?

answer:To find the composite functions, we follow these steps: 1. For #f(g(x))#, we substitute #g(x)# into #f(x)#: [ f(g(x)) = f(-x + 3) = 4(-x + 3)^2 ] 2. For #g(f(x))#, we substitute #f(x)# into #g(x)#: [ g(f(x)) = g(4x^2) = -4x^2 + 3 ] Thus, the compositions are: [ f(g(x)) = 4(-x + 3)^2 ] [ g(f(x)) = -4x^2 + 3 ]

question:Find the cross product of the following vectors: vec{a} = left( begin{array}{c} frac{19}{8} -frac{15}{8} -frac{15}{2} end{array} right) and vec{b} = left( begin{array}{c} -frac{1}{8} -frac{11}{2} -frac{63}{8} end{array} right)

answer:The cross product of two vectors vec{a} = (a_1, a_2, a_3) and vec{b} = (b_1, b_2, b_3) is defined as: vec{a} times vec{b} = left( begin{array}{c} a_2b_3 - a_3b_2 a_3b_1 - a_1b_3 a_1b_2 - a_2b_1 end{array} right) Plugging in the values of vec{a} and vec{b}, we get: vec{a} times vec{b} = left( begin{array}{c} left(-frac{15}{8}right)left(-frac{63}{8}right) - left(-frac{15}{2}right)left(-frac{11}{2}right) left(-frac{15}{2}right)left(-frac{1}{8}right) - left(frac{19}{8}right)left(-frac{63}{8}right) left(frac{19}{8}right)left(-frac{11}{2}right) - left(-frac{15}{8}right)left(-frac{1}{8}right) end{array} right) Simplifying each component, we get: vec{a} times vec{b} = left( begin{array}{c} frac{1695}{64} -frac{1257}{64} frac{851}{64} end{array} right) Therefore, the cross product of vec{a} and vec{b} is left( begin{array}{c} -frac{1695}{64} frac{1257}{64} -frac{851}{64} end{array} right). The answer is vec{a} times vec{b} = left( begin{array}{c} -frac{1695}{64} frac{1257}{64} -frac{851}{64} end{array} right)

question:Find the derivative of the function {eq}y=frac{80}{x^7}{/eq}.

answer:To find the derivative of the function {eq}y=frac{80}{x^7}{/eq}, we can rewrite it as {eq}y=80x^{-7}{/eq}. Applying the power rule for differentiation, which states that {eq}frac{d}{dx}(x^n) = nx^{n-1}{/eq}, we get: {eq}begin{align*} y' &= frac{d}{dx}(80x^{-7}) &= 80 cdot (-7)x^{-7-1} &= -560x^{-8} &= -frac{560}{x^8}. end{align*}{/eq} Thus, the derivative of the function is {eq}-frac{560}{x^8}{/eq}.

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