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question:If Lansing Inc.'s pretax income increased to 19,000,000, what would their total taxes paid be using the same tax rate schedule from Exhibit 11.6?
answer:Lansing's taxes due would be: 5,150,000 + 38% of income above 15,000,000 5,150,000 + (19,000,000 - 15,000,000)*0.38 = 6,530,000
question:What term describes the phenomenon where people's attention is constantly being pulled towards their digital devices, leading to a disconnect from their surroundings?
answer:Culture of distraction
question:Compute the square of the following matrix: [ begin{bmatrix} -2 & -3 & -2 -1 & -1 & -2 2 & 2 & -1 end{bmatrix} ]
answer:The square of the given matrix is: [ begin{bmatrix} (-2)(-2) + (-3)(-1) + (-2)(-2) & (-2)(-1) + (-3)(-1) + (-2)(-2) & (-2)(2) + (-3)(2) + (-2)(-1) (-1)(-2) + (-1)(-1) + (-2)(2) & (-1)(-1) + (-1)(-1) + (-2)(-2) & (-1)(2) + (-1)(2) + (-2)(-1) (2)(-2) + (2)(-1) + (-1)(-1) & (2)(-1) + (2)(-1) + (-1)(-2) & (2)(2) + (2)(-2) + (-1)(-1) end{bmatrix} ] Simplifying each element: [ begin{bmatrix} 4 + 3 + 4 & 2 + 3 + 4 & -4 - 6 + 2 2 + 1 - 4 & 1 + 1 + 4 & -2 - 2 + 2 -4 - 2 + 1 & -2 - 2 + 2 & 4 - 4 + 1 end{bmatrix} ] This further simplifies to: [ begin{bmatrix} 11 & 9 & 2 -1 & 6 & 0 -5 & 0 & 1 end{bmatrix} ] Therefore, the square of the matrix is: [ begin{bmatrix} 11 & 9 & 2 -1 & 6 & 0 -5 & 0 & 1 end{bmatrix} ]
question:How do you find all values of c that satisfy the Mean Value Theorem for integrals for f(x) = x^4 on the interval [-4, 4]?
answer:The Mean Value Theorem for integrals states that if f(x) is continuous on the closed interval [a, b] and differentiable on the open interval (a, b), then there exists a number c in (a, b) such that f'(c) = (f(b) - f(a))/(b - a). In this case, a = -4, b = 4, and f(x) = x^4. So, we need to solve the equation f'(c) = (f(4) - f(-4))/(4 - (-4)). First, we find f'(x) and f(4) - f(-4): f'(x) = 4x^3 f(4) - f(-4) = (4^4) - ((-4)^4) = 256 - 256 = 0 Now, we can substitute these values into the equation f'(c) = (f(4) - f(-4))/(4 - (-4)): 4c^3 = 0 This equation is satisfied when c = 0. However, we need to discard this solution because it is not in the interval (-4, 4). Therefore, there are no values of c that satisfy the Mean Value Theorem for integrals for f(x) = x^4 on the interval [-4, 4]. To find all values of c that satisfy the Mean Value Theorem for integrals for f(x) = x^4 on the interval [-4, 4], we need to solve the equation f'(c) = (f(4) - f(-4))/(4 - (-4)).