answer:The chemical equation is reversed, so we take the reciprocal of the original equilibrium constant to obtain the new equilibrium constant: {eq}rm K_{new} = dfrac{1}{K} K_{new} = dfrac{1}{1.7times10^{-2} } boxed{ mathbf{ K_{new} = 58.8 }} {/eq}

answer:Given: f(x) = (x - 5)(2x + 3) Expand the function using the distributive property: begin{align} f(x) &= 2x^2 - 7x - 15 end{align} Find the derivative to determine the slope of the tangent line: begin{align} f'(x) &= 4x - 7 f'(2) &= 4(2) - 7 = 1 end{align} Evaluate the function at {eq}x = 2{/eq} to find the y-coordinate of the point: begin{align} f(2) &= 2(2)^2 - 7(2) - 15 = -19 end{align} Use the point-slope form to find the equation of the tangent line: begin{align} y - (-19) &= 1(x - 2) y + 19 &= x - 2 y &= x - 21 end{align} Therefore, the equation of the tangent line is {eq}y = x - 21{/eq}.

answer:Developed Markets: * High per capita income * High human capital index * Advanced technological infrastructure * Large investments * Stable economies * Countries with developed markets are typically considered developed countries. Emerging Markets: * Transitioning from developing to developed status * Moderate per capita income * Developing capital markets * Growing industrial production * Countries with emerging markets are typically considered developing countries. Frontier Markets: * Less developed than emerging markets * Smaller in size and capital * Higher risk associated with investments * Countries with frontier markets are typically considered middle-income countries. These market classifications help determine a country's economic standing because they reflect factors such as income levels, industrial development, and investment opportunities. Developed markets indicate a high standard of living and economic stability, while emerging and frontier markets suggest potential for growth but also higher risk.

answer:The remaining activity of a radioactive isotope after a certain number of half-lives can be calculated using the following pattern: - After 1 half-life, the remaining activity is 50%. - After each additional half-life, the remaining activity is halved. So, after 5 half-lives, the remaining activity of rhenium-186 will be: {eq}displaystyle frac{50%}{2^4} = frac{50%}{16} = 3.125% {/eq} Thus, 3.125% of the original activity of rhenium-186 will remain after 5 half-lives.